A thief is stopped by a policeman from a distance of 450 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 7 km/h and that of policeman as 12 km/h, how far the thief would have run, before he is over taken?
A) 504 metres B) 756 metres C) 378 metres D) 630 metres
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Answer:
The distance between the Thief and the Policeman was 400- metres.
The difference in speed of both was=(9–5)= 4Km/h= 4 x 5/18= 20/18= 10/9 metres / sec.
So 400/(10/9)=400x9/10 =360- seconds. =360/60 =6- minutes.
That is after 6- minutes the thief would have run 5 x 5/18 x 360= 500- metres, before being caught by the Police man.
The answer is 500 but there is no option
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