Question

A thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 m ahead of the policeman, then the time required for the policeman to catch the thief will be

Answer 1

Answer:

Time required for the policeman to catch the thief will be $<b>3 minutes$

Explanation:

The relative speed between police and thief = 10 - 8 $\frac {km}{h}$

= 2 $\frac {km}{h}$

$\implies \frac {1\:km}{h}$ = $\frac {5}{18}$

$\implies \frac {2\:km}{h}$ = $\frac {2\:\times\:5}{18}$

$\implies \frac {2\:km}{h}$ = $\frac {10}{18}$

Distance between police and thief = 100 m

Time = $\frac {Distance}{Speed}$

= $\frac {100\:\times\:18}{10}$

= 180 seconds

= 3 minutes

•°• Time required for the policeman to catch the thief will be $<b>3 minutes$

Answer 2

Explanation: 18km/hr

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