A thief runs at a speed of
32 mtr/ sec and a policeman runs behind him at a speed of 48 mtr/sec.
But after 6 sec running how many metes will the policeman catch the thief?
Answers
Given : A thief runs at a speed of 32 mtr/ sec and a policeman runs at a speed of 48 mtr/sec but after 6 sec .
To Find : after how many metes will the policeman catch the thief
Solution:
Distance = Speed x time
Let say Policeman catches the thief after t sec
Speed of policeman = 48 m/s
Distance covered by policemen = 48t m
Speed of Thief = 32 m/s
Time for thief = t + 6 sec
Distance covered by policemen = 32(t + 6) m
48t = 32(t + 6)
=> 3t = 2(t + 6)
=> 3t = 2t + 12
=> t = 12
Distance covered by policemen = 48t
= 48 x 12
= 576 m
After running 576 m policeman catch the thief
Another Way : in 6 Sec Thief covered Distance = 32 x 6 = 192 m
Relative Speed of Policeman = 48 - 32 = 16 m/s
Time Taken by policeman = 192/16 = 12 sec
Distance covered by policemen = 48 * 12 = 576 m
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