Math, asked by Anonymous, 7 months ago

A thief runs with a uniform speed of 100m/min. After one min a policeman runs after the thief to catch him. He goes with a speed of 100m/min in first min and increase his speed by 10m/min every succeeding min. After how many min the policeman will catch the thief.

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Answers

Answered by Anitaddas
2

Answer:

Let the police catch the thief in n min

As the thief ran 1 min before the police

Time taken by the thief before being caught =(n+1) min

Distance travelled by the thief in (n+1) min

=100(n+1)m

Speed of police in 1

st

min

=100m/min

Speed of police in 2

nd

min=110m/min

Speed of police in3

rd

min =120m/min. and so on

∴100,110,120,... this forms an AP

Total distance travelled by the police in n min =

2

n

(2×100+(n−1)10)

On catching the thief by police,distance traveled by thief= distance travelled by the police

⇒100(n+1)=

2

n

(2×100+(n−1)10)

⇒100n+100=100n+

2

n

(n−1)10

⇒100=n(n−1)5

⇒n

2

−n−20=0

⇒(n−5)(n+4)=0

⇒n−5=0,n+4=0

⇒n=5 OR n=−4(but this is not possible)

so, n=5

Time taken by the policeman to catch the thief=5min

Answered by shivapriyan23
13

Answer :

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Step-by-step explanation:

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bioyil tamil kanditt chotichatatto

sry repot cheyyanam enn tonniyal cheyto okk

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