Question

A thief steals a car at 1:30 p.M. And drives it at 45 km an hour. The theft is discovered at 2 p.M. And the owner sets off in another car at 50 km an hour. He will overtake the thief at ?

Answer 1

Answer:

time take = 2 p.m. - 1:30 pm = 30 min = 1800 s

speed = 45 km/hr. = 12.5 m/s

therefore, distance covered = speed × time = 1800×12.5 = 22500 m

now,

speed = 50 km/hr. = 13.8888888889 m/s

distance = 22500m

therefore, time = distance ÷speed = 22500÷13.888888889 = 1619.9999999987 s = 27 min.

thus, he will overtake the theif at 1:57 p.m.