Question

A thief steals a car at 1.30pm and drives it 45 km an hour. The theft is discovered at 2pm and the owner sets off in another car at 50km an hour. he will overtake the thief at what time?

Answer 1

As per statement both owner and thief have to reach same destination to catch hold the thief and recover car.
Also thief had already taken 1 / 2 h more than owner.
Let owner takes T time to reach destination to catch thief. Then thief will take T +.0.5 time to reach same destination.
Speed of owner = 50 Km / h
Speed of thief = 45 Km / h
50T = 45 (T + 0.5)
50T = 45T + 22.5
50T - 45T = 22.5
5T = 22.5
T = 22.5 / 5
T = 4.5
Therefore, owner has taken 4.5 hours to catch thief.
Means he had started at 2 pm and cached thief at 6.30 pm.

Answer 2

Answer:

As per statement both owner and thief have to reach same destination to catch hold the thief and recover car.

Also thief had already taken 1 / 2 h more than owner.

Let owner takes T time to reach destination to catch thief. Then thief will take T +.0.5 time to reach same destination.

Speed of owner = 50 Km / h

Speed of thief = 45 Km / h

50T = 45 (T + 0.5)

50T = 45T + 22.5

50T - 45T = 22.5

5T = 22.5

T = 22.5 / 5

T = 4.5

Therefore, owner has taken 4.5 hours to catch thief.

Means he had started at 2 pm and cached thief at 6.30 pm.