a thief steals a car at 2.30 p.m. and drives it at 60 kmph. the theft is discovered at 3 p.m. and the owner sets off in another car at 75 kmph. when will he overtake the thief?
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Answered by
4
Answer:
5 pm
step by step explanation:
Suppose the thief is overtaken x hrs after 2.30 pm
The, distance covered by the thief in x hrs = Distance covered by owner in (x−12)hrs
∴60x=75(x−1/2)
15x=752
x=52 hrs
So, the theif is overtaken at 5 pm
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Answered by
1
Answer
3:30 pm baje app 'phouge
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