Physics, asked by pkumar9918, 2 months ago

A thin bar pendulum, one meter long is allowed to oscillate under the influence ofgravity about a horizontal axis passing through its one end. Its length of equivalent simple pendulum is
2 points
0.34 m
0.67 m
1.0 m
None of the above​

Answers

Answered by reshmabhagat943
1

Answer:

nove of the above

Explanation:

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Answered by VaibhavSR
0

Answer:

Explanation:

M.I. of uniform bar about the axis passing through its one end and perpendicular to its length

is given by,

I=ml²/12=mk²

k=L/√12

The length of equivalent simple pendulum is,

L =l+k²/l=l+L²/12l

=0.6667m

#SPJ3

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