Physics, asked by supravo76, 7 months ago

A thin biconvex lens of refractive index 3/2 is placed on a horizontal plane mirror
as shown in the figure. The space between the lens and the mirror is then filled with water of
refractive index 483. It is found that when a point object is placed 15 cm
Love the lens on its principal axis, the object coincides with its own image.
On repeating with another liquid, the object and the image again coincide at a
distance 25 cm from the lans. Calculate the refractive index of the liquid.

Answers

Answered by rr7172283
0

Explanation:

Let f1 be the focal length of convex lens; radius of curvature of each curved face is R. 1f1 = (m - 1) { 1R - (1-R) } = (μ - 1) 2R f1 = R2(μ-1) = R2 ...

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