Question

A thin circular ring of mass m and radius r is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring. The ring will then rotate with an angular velocity

Answer 1

Answer:

ω = Mω/(M+2m)

Explanation:

Using conservation of angular momentum

Iω = I°ω°

M$R^{2}$ω = (M$R^{2}$ + m$R^{2}$ + m$R^{2}$)ω°

Mω = (M + 2m)ω°

ω = Mω/(M+2m)

Answer 2

• Two objects each of mass m, are attached gently to the opposite ends of a diameter of the ring. Find the new angular velocity of the ring.

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