Question

A thin, convergent lens has a focal length of 8.00 cm. If a real, inverted image is located 12.0 cm to the right of the lens, where is the object located? (a) 12.0 cm to the left of the lens (b) 24.0 cm to the right of the lens (c) 24.0 cm to the left of the lens (d) 18.0 cm to the right of the lens (e) 18.0 cm to the left of the lens

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

The object is located 24.0 cm to the left of the lens i.e.option(c).

Explanation:

We will use the lens formula to solve this question. It is given as,

$\frac{1}{v}-\frac{1}{u} =\frac{1}{f}$         (1)

Where,

v=image distance from the lens

u=object distance from the lens

f=focal length of the lens

From the question we have,

f=8cm         (Focal length is positive for convergent lens)

v=12 cm     (Image is formed to the right of the lens)

By substituting the values of f and v in equation (1) we get;

$\frac{1}{12}-\frac{1}{u} =\frac{1}{8}$

$\frac{1}{u}=\frac{1}{12}-\frac{1}{8}$

$\frac{1}{u}=\frac{2-3}{24}$

$\frac{1}{u} =\frac{-1}{24}$

$u=-24 cm$

The object is located 24 cm to the left of the lens.

Hence, the correct answer among the given options is (c)i.e.24.0 cm to the left of the lens.