A thin disc of diameter 0.8m is rotated about an axis through its centre by application of a force120N find the
torque acting on the disc.
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torque acting on the disc would be 48 Nm
given, diameter of the thin disc , d = 0.8 m
radius of the thin disc, r = 0.4 m
force applied on disc, F = 120 N
torque acting on the disc = seperation between point of observation to axis of rotation × force applied
= 0.4 m × 120 N
= 48 Nm
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