Question

a thin door of width 0.8m and mass 30kg can rotate about a vertical axis along its hinges. a bullet of mass 20gm ans speed 300m/s strikes at the centre of the door in a direction perpendicular to the plane of the door and gets embedded. find the angular speed of the door.

Answer 1

Given:Mass of the bullet,m=10g=10×10−3kg

Given:Mass of the bullet,m=10g=10×10−3kgVelocity of the bullet,v=500m/s

Given:Mass of the bullet,m=10g=10×10−3kgVelocity of the bullet,v=500m/sThickness of the door,L=1m

Given:Mass of the bullet,m=10g=10×10−3kgVelocity of the bullet,v=500m/sThickness of the door,L=1mRadius of the fdoor,r=2m

Given:Mass of the bullet,m=10g=10×10−3kgVelocity of the bullet,v=500m/sThickness of the door,L=1mRadius of the fdoor,r=2mMass of the door,M=12kg

Given:Mass of the bullet,m=10g=10×10−3kgVelocity of the bullet,v=500m/sThickness of the door,L=1mRadius of the fdoor,r=2mMass of the door,M=12kgAngular momentum imparted by the bullet on the bullet em

Answer 2

Answer:

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