Question

A thin film of resistor in a solid state circuit has a
thickness of 1 µm and is made of nichrome of resistavity
10−6 Ωm. Calculate the resistance available between
opposite edge of a 1 mm2
area of film.
If it is square shaped
if it is rectangular, 20 times as long as its breadth

Answer 1

Answer:

Hope this will help you

Explanation:

Answer 2

Concept:

A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance.

Given:

The thickness of the resistor is $1\mu m$.

The resistivity is $10^{-6}\Omega m$.

The area of the film is $1mm^2$.

Find:

The resistance between the opposite edges if the film is square shaped and the resistance if the film is rectangular shaped with $20$ times as long as its breadth.

Solution:

Resistivity, $\rho=10^{-6}\Omega m$

The thickness of the resistor, $t=1\mu m=10^{-6}m$

Area, $A=1mm^2=10^{-6}m^2$

The formula for resistance is given as:

$R=\rho \frac{l}{A}$

When the film is square-shaped.

The area is equal to the length of a side times thickness.

$R=\rho\frac{l}{l\times t}$

$R=\frac{\rho}{t}$

$R=\frac{10^{-6}}{10^{-6}} =1\Omega$

When the film is rectangular in shape.

Length is $l$ and breadth $w=20l$

$R=\rho \frac{l}{A}$

$R=\rho\frac{l}{l\times w\times t}$

$R=\frac{\rho}{w\times t}$

$R=\frac{10^{-6}}{20\times 10^{-6}}$

$R=0.05\Omega$

The resistance when it is square shaped is $1\Omega$ and when it is rectangular shaped is $0.05\Omega$.

#SPJ2