Math, asked by tovcz9339, 25 days ago

A thin hoop with a mass of 5.0kg rotates about a perpendicular axis through its center a force F is exerted tangentially to the hoop if the hoops radius is 2.0 m and it’s rotating with an angular acceleration of 2.5 rad/s calculate the mangnitude of F

Answers

Answered by Shafashafa123

0

Answer:

25 N

Step-by-step explanation:

F = m*a =m*alpha*r Where alpha is the angular acceleration.

Therefore, F =5*2.5*2 =25N

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