a thin iron wire,when bent in the form of a square, enclose an area of 484cm^2.if the same wire is bent in the form of a circle than find the area enclosed by the circle.
Answers
Given that Area of the square formed by bending a copper wire = 484cm^2.
We know that side of the square = s^2
s^2 = 484
s = 22cm.
We know that perimeter of the square = 4 * s
= 4 * 22
= 88cm.
Therefore the length of the wire = 88cm.
Now,
Given that the same wire is bent into a form of circle.
Circumference of circle = Length of wire
2pir = 88
2 * 22/7 * r = 88
44/7 * r = 88
44 * r = 88 * 7
44 * r = 616
r = 616/44
r = 14.
We know that Area of circle = pir^2
= 22/7 * (14)^2
= 22 * 14 * 2
= 616cm^2.
Therefore the area enclosed by the circle = 616cm^2.
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