Math, asked by manishlodhi, 1 year ago

a thin iron wire,when bent in the form of a square, enclose an area of 484cm^2.if the same wire is bent in the form of a circle than find the area enclosed by the circle.​

Answers

Answered by goyal1102001
1

Given that Area of the square formed by bending a copper wire = 484cm^2.

We know that side of the square = s^2

                                 s^2 = 484

                                 s = 22cm.

We know that perimeter of the square = 4 * s

                                                                 = 4 * 22

                                                                 = 88cm.

Therefore the length of the wire = 88cm.

Now,

Given that the same wire is bent into a form of circle.

Circumference of circle = Length of wire

2pir = 88

2 * 22/7 * r = 88

44/7 * r = 88

44 * r = 88 * 7

44 * r = 616

r = 616/44

r = 14.

We know that Area of circle = pir^2

                                                = 22/7 * (14)^2

                                                = 22 * 14 * 2

                                                = 616cm^2.

Therefore the area enclosed by the circle = 616cm^2.

Hope this helps! ------

GOOD LUCK..

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