Question

A thin isosceles prims with angle 4º and refractive index 1.5 is placed inside a transparent tube with
water (refractive index = ?) as shown. The deviation of light due to prism will be
water (refractive index = ) as shown. The deviation of light due to prism will be
o 0.8° upward
O 0.8°downward​

Answer 1

Given : A thin isosceles prims with angle 4º and refractive index 1.5 is placed inside a transparent tube with water (refractive index = 5/4) as shown.

To find : The deviation of light due to prism.

solution : deviation angle of prism, δ = (μ₁/μ₂ - 1)A

here μ₁ is refractive index of prism,

μ₂ is refractive index of transparent tube with water,

δ is angle of deviation and A is angle of prism.

μ₁ = 1.5 , μ₂ = 5/4, A = 4°

so, δ = [1.5/(5/4) - 1] × 4° = [1.5/1.25 - 1]4°

= 0.2 × 4 = 0.8°

here deviation angle is positive so, deviation is downward.

Therefore deviation of light due to prism will be 0.8° downward.