a thin long conductor has linear charge density of 20 microcoulomb per metre calculate electric field intensity at a point 5 cm from it .draw a graph to show variation of electric field intensity with distance from the conductor.
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Answer:
Explanation:
given λ =20×10⁻⁶ C/m
r= 5×10⁻²m
Electric field intensity
= λ / 2πε₀r
= 20×10⁻⁶×18×10⁹/5×10⁻²
= 72×10⁷
= 7.2×10⁶N/C
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given λ =20×10⁻⁶ C/m
r= 5×10⁻²m
Electric field intensity
= λ / 2πε₀r
= 20×10⁻⁶×18×10⁹/5×10⁻²
= 72×10⁷
= 7.2×10⁶N/C
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