Question

A thin metal dise of radius 0.25m and mass
2kg starts from rest and rolls down an
inclined plane. If its rotational kinetic
energy is 4J at the foot of the inclined
plane, then its linear velocity at the sam
point ​

Answer 1

Explanation:

KE = 1/2 Iw^2 = 4

I disc = 1/2 mr^2

v = rw

w = v/r

4 = 1/4 × 2 × r^2 × (v/r) ^2

v^2 = 16/2 = 8

therefore v= √8 ms-1