A thin metal iron sheet is rhombus in shape,with each side 10 m.If one of its diagonals is 16 m.find,find the cost of painting its both the sides at the rate of Rs 6 per m^2.Also find the distance between the opposite sides of this rhombus.
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Side AB = 10 m.
Diagonal AC = 16 m.
Area = AC × BD / 2 m^2
Area of both sides = AC × BD = 16 BD m^2
cost of painting both sides = ₹ 16 BD * 6 = ₹ 96 BD.
In a Rhombus, AC² + BD² = 4 AB².
BD² = 4 * 10² - 16² = 144
BD = 12.
So Cost = ₹ 1, 152.
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h = distance between parallel sides.
Area ABCD = AC × BD/ 2 = AB × h
h = 16 × 12 /(2×10) = 9.6 m.
Diagonal AC = 16 m.
Area = AC × BD / 2 m^2
Area of both sides = AC × BD = 16 BD m^2
cost of painting both sides = ₹ 16 BD * 6 = ₹ 96 BD.
In a Rhombus, AC² + BD² = 4 AB².
BD² = 4 * 10² - 16² = 144
BD = 12.
So Cost = ₹ 1, 152.
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h = distance between parallel sides.
Area ABCD = AC × BD/ 2 = AB × h
h = 16 × 12 /(2×10) = 9.6 m.
kvnmurty:
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