Question

A thin metallic square plate has length l when it is heated from 0C to 100C it's length increases by 1%what is the%increase in the area of the plate?

Answer 1

Answer:

Given:

ΔT=100−0=100°C

ΔL/L=length=L=1%=1/100=0.01

ΔL=αLΔT

ΔL/L=αx100

0.01=αx100

α=0.01/100=1×10

−4

Given Area of copper plate =2LxL=2L

2

By thermal expansion theory,

ΔA=βAΔT

ΔA/A=βΔT

but,

β=2α

ΔA/A=2αΔT

=2×1×10

−

4×100

=2×10

−

2

ΔA/A×100=2×10

−2

×100=2%

Explanation:

Answer 2

Answer:

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