Question

a thin prism of 60 angles gives a deviation of 30 what is the refractive index of the material

Answer 1

Answer:

n=1.41

Step by step explanation:

It is given that:

• The angle of the prism 'A' is $60^o$
• The angle of minimum deviation 'D' is $30^o$

$n=\frac{sin(\frac{A+D}{2} )}{sin(\frac{A}{2})}\\ \\n=\frac{sin(\frac{60+30}{2} )}{sin(\frac{60}{2})}\\ \\n=\frac{sin(45^o)}{sin30^o}\\ \\n=\frac{1}{\sqrt{2}}*2\\ \\n=\frac{2}{\sqrt{2} }=1.41$