Physics, asked by talekar805, 1 year ago

A thin ring has mass 0.25 kg radius 0.5 cm its moments of inertia about an axis passing through its centre and perpendicular to its plane is
0.0625kg m
0.625 kg m
6.25 kg m
62.5 kg

Answers

Answered by AaravChhabra3008
0

Answer:

Hence, moment of inertia about an axis passing through center of the ring and perpendicular to its plane is 0.0625 kg/m^2

Explanation:

hope it helps

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