A thin ring has mass of 0.25 kg and radius 0.5m . It's moment of inertia about an axis passing through its centre and perpendicular to its plane is .?
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Answered by
5
wee know that p=mv
•: 0.25×0.5= 0.125kg/ms
•: 0.25×0.5= 0.125kg/ms
tulika7:
is it right??
yes
because p=mv
it is formula of linear momentum
yes so what
question is asking about moment of inertia ,which ie equal to mass × radius²
oh sorry iam wrong
it is question of rotation motion of class 11
it's okk
oh iam in 9th class
Answered by
3
moment of inertia = €M×R²
= 0.25×0.5²
=0.0625
= 0.25×0.5²
=0.0625
Thanks
mention not
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