Physics, asked by saonijain4321, 10 months ago

A thin ring of 10 cm radius carries a uniformly distributed charge. The ring rotates at a constant angular speed of 40 π rad s⁻¹ about its axis, perpendicular to its plane. If the magnetic field at its centre is 3.8 × 10⁻⁹ T, then the charge carried by the ring is close to (μ₀ = 4π × 10⁻⁷ N/A²).
(A) 2 × 10⁻⁶ C (B) 7 × 10⁻⁶ C
(C) 4 × 10⁻⁵ C (D) 3 × 10⁻⁵ C

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Answered by shreyash1505
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