Physics, asked by cheerycharan, 1 year ago

A thin rod mass M and length L is bent into a circular ring.the expression for moment of inertia of ring about an axis passing through its diameter is

Answers

Answered by prachi60

According to theorem of perp. axis, the m.i of ring about it,s diameter is equal to the sum of It's m.i about two perp. diameter suppose AB and CD
I.AB + I.CD= I.yy'
2I= MR2
I = MR2/2

Previous Question

Next Question

Similar questions

English, 7 months ago

Fill in the blanks with Simple Present and Present Continuous tense. 1. Every Monday, Sally (drive) _______________her kids to football practice. 2. Usually, I (work)________________ as a secretary at ABT, but this summer I (study)___________________ French at a language school in Paris. That is why I am in Paris. 3. Shhhhh! Be quiet! John (sleep)_____________________________. 4.

Math, 7 months ago

make your own tiles pattern...

Social Sciences, 7 months ago

STATE WHETHER THE FOLLOWING STATEMENTS ARE TRUE OR FALSE: 7. The Iqtadars were called Samantas.

Biology, 1 year ago

in which kingdom does an organism has a well defined nucleus and organelles...

English, 1 year ago

Was Bonnin successful in hiding herself? What did they do after finding her?.....Need Content quality answer>>>>Don't copy from net...

Science, 1 year ago

A body of mass 5 kg is moving with a velocity of 10 m/s.What will be the ratio of its initial and final kinetic energy, if the mass is doubled and its velocity is halved ?

English, 1 year ago

How easy/ difficult do you think it would be for you......?

Math, 1 year ago

The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white-washing its curved surface at the rate of Rs 210 per 100 m 2 .