A thin rod of a length = 0.1 m and m=120gm
find mor about Transverse axis passing through
1)center of mass
2)One end
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Answer:
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Explanation:
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Answered by
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Answer:
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Explanation:
Calculation the M.I of a thin uniform rod of mass 100g and length 60c about an axis perpendicular
where M=100g
l=60cm= length of the rod
Moment of inertia of a thin uniform rod about a transverse axis
Passing through its centre is given by
I−0=I=
12
Ml
2
(for rod)
By parallel axis theorem, we get,
I
0
=I
g
+Mh
2
∴I
0
=
12
Ml
2
+M(
4
l
)
2
∴I
0
=
12
Ml
2
+
16
Ml
2
I
0
=
48
4Ml
2
+3Ml
2
I
0
=
48
7Ml
2
=
48
7×100×60
2
=52500g.cm
2
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