a thin rod of length 10cm is placed along the axis of concave mirror of focal length 30cm such that its real image just touches the rod what is the length of image
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Answer:
3cm is the answer length of answers
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Let l be length of image
then
m=
3
f
l
l=
3
mf
Also image of one end coincide with object
u
′
=2f
u
′
=u+
3
f
u=2f−
3
f
=
3
5f
v=−(u+
3
f
+
3
mf
)
Putting mirror formula
u+
3
f
+
3
mf
1
+
u
1
=
f
1
5f+f+mf
3
+
5f
3
=
f
1
m+6
1
=
15
2
m=
2
3
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