A thin rod of length 24 feet is cut into
rods of equal size and joined so as to
form a skeleton cube. What is the area
of one of the faces of the largest cube
thus constructed ?
Answers
Answered by
4
Answer:
area of one face of the cube = 4 sq feet
Step-by-step explanation:
a cube has 12 edges (line segment) of equal length
a 24 feet rod has to be cut into 12 pieces of equal length to make a cubicle skeleton
24/12 = 2 feet
we get 6 faces of equal area in a cube
sides of cube is 2 feet
area of one face of the cube
s × s = 2 × 2 = 4 sq feet
hope you get your answer
Similar questions