Question

A thin rod of length L and mass M is held vertically with one end on the floor and is allowed to fall. Find the velocity of the other end when it hits the floor, assuming that the end on the floor does not slip

Answer 1

Explanation:

see the diagram first

at point p total enrgy

=K.E+P.E

KE=0 as v =0

P.E =mgh

mg×l/2..........(1)

at point O yotal energy

=K.E+P.E

P.E=0 as we assume it as mean point

=1/2mv^2.............(2)

equating 1 and 2

mg×l/2=1/2mv^2

v=under root g

v=3.13m/s