Question

A thin rod of length L and uniform crosssection is pivoted at its lowest point P inside a stationary homogeneous and non-viscous liquid.The rod is free to rotate in a vertical plane about a horizontal axis passing through P. The density $d_1$ of the material of the rod is smaller than the density $d_1$ of the liquid. The rod is displaced by small angle $\theta$ from its equilibrium position and then released. Show that the motion of the rod is simple harmonic and determine its angular frequency in terms of the given parameters.

Answer 1

Answer:

ndrkeeote passing through P. The density $d_1$ of the material of the rod is smaller than the density $d_1$ of the liquid. The rod is displaced by small angle $\theta$ from its equilibrium position and then released. Show that the motion of the rod is simple harmonic and determine its angular frequency in terms of the given parameters.

Answer 2

Explanation:

from its equilibrium position and then released. Show that the motion of the rod is simple harmonic and determine its angular frequency in terms of the given parameters.