A thin smooth rod of length L and mass M is rotating freely with angular speed ω₀ about an axis perpendicular to the rod and passing through its centre. Two beads of mass m and negligible size are at the centre of the rod initially. The beads are free to slide along the rod. The angular speed of the system, when the beads reach the opposite ends of the rod will be:-
(A) Mω₀/(M + 3m)
(B) Mω₀/(M + m)
(C) Mω₀/(M + 2m)
(D) Mω₀/(M + 6m)
Answers
Explanation:
A thin smooth rod of length L and mass M is rotating freely with angular speed ω₀ about an axis perpendicular to the rod and passing through its centre. Two beads of mass m and negligible size are at the centre of the rod initially. The beads are free to slide along the rod. The angular speed of the system, when the beads reach the opposite ends of the rod will be:-
(A) Mω₀/(M + 3m)
(B) Mω₀/(M + m)
(C) Mω₀/(M + 2m)✓✓
(D) Mω₀/(M + 6m)
Answer:
A thin smooth rod of length L and mass M is rotating freely with angular speed ω₀ about an axis perpendicular to the rod and passing through its centre. Two beads of mass m and negligible size are at the centre of the rod initially. The beads are free to slide along the rod. The angular speed of the system, when the beads reach the opposite ends of the rod will be:-
(A) Mω₀/(M + 3m)
(B) Mω₀/(M + m)
(C) Mω₀/(M + 2m)✔✔✔
(D) Mω₀/(M + 6m)