Question

A thin spherical shell of total mass M and radius R is held fixed. There is a small hole in the shell. A mass
m is released from rest at distance R from the hole. This mass subsequently moves under the gravitational force
of the shell. How long does the mass take to travel from the hole to the point diametrically opposite ?​

Answer 1

The  mass have to travel t = 2√R^3 / GM from the hole to the point.

Explanation:

velocity at the moment entering the hole from conservation of energy.

Ui + Ki = Uf + Kf

−GMm / 2R+0 = − GMm / R + 1/2mv^2

v = √ GM / R

Since inside no gravitational field so v is constant .

t=2R / v = 2√R^3 / GM

t = 2√R^3 / GM

The mass have to travel t = 2√R^3 / GM from the hole to the point.

Also learn more

What is angular momentum???

https://brainly.in/question/6710222