Physics, asked by anshikatiwari6478, 1 year ago

A thin square plate of mass m and side 'a' is hinged about ab so as to execute small oscillations about ab. The time period of oscillations is


Anonymous: Hi

Answers

Answered by Fatimakincsem
0

Thus the value of time period of oscillation is T = 2π  √2/3 g

Explanation:

We are given that:

  • Mass of plate = m
  • Side of plate = a

Solution:

Formula:

T = 2π √l/g

Where T = time period in seconds

L  = length

g  = gravity

Side 'a' is hinged about AB = 1/3 AB

Now the value of L will be 1-1/3 = 2/3

Put the values in the formula

T = 2π  √2/3 / g

Thus the value of time period is T = 2π  √2/3 g

Similar questions