A thin square plate of mass m and side 'a' is hinged about ab so as to execute small oscillations about ab. The time period of oscillations is
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Thus the value of time period of oscillation is T = 2π √2/3 g
Explanation:
We are given that:
- Mass of plate = m
- Side of plate = a
Solution:
Formula:
T = 2π √l/g
Where T = time period in seconds
L = length
g = gravity
Side 'a' is hinged about AB = 1/3 AB
Now the value of L will be 1-1/3 = 2/3
Put the values in the formula
T = 2π √2/3 / g
Thus the value of time period is T = 2π √2/3 g
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