Physics, asked by MacEyeMow, 2 months ago

A thin straight infinitely long wire of linear charge density is enclosed by a cylindrical surface of radius r & length l. Its axis coinciding with the length of the wire .
Obtain the expression of the electric field , indicating the directions at a point on the
surface of cylindrical surface ?

Answers

Answered by Anonymous
5

Answer:

Charge enclosed by the cylindrical surface = λl By Gauss Theorem, electric flux = 1/εo × charge enclosed. = 1/εo(λl)l.

l hope it will help u ☺️☺️☺️

Answered by Anonymous
1

Answer:

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Explanation:

  1. Obtain the expression of the electric field , indicating the directions at a point on the
  2. Obtain the expression of the electric field , indicating the directions at a point on thesurface
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