Question

A thin straight infinitely long wire of linear charge density is enclosed by a cylindrical surface of radius r & length l. Its axis coinciding with the length of the wire .
Obtain the expression of the electric field , indicating the directions at a point on the
surface of cylindrical surface ?

❤⭐ SELECT ANY ONE WISH ⭐❤​

Answer 1

Answer:

Charge enclosed by the cylindrical surface = λl By Gauss Theorem, electric flux = 1/εo × charge enclosed. = 1/εo(λl)

Step-by-step explanation:

Wish 6 Prince

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Answer 2

Answer:

I choose wish 4

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Step-by-step explanation:

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