a thin straight rod of length L having a charge q uniformly distributed over its length lies along the x axis with its midpoint at arigin what is the field intensity created at the point p (0,1/2)
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Answer
Correct option is
C
4πϵ
0
d(d+l)
2
λl
Let's first find Electric field due to the rod on x-axis, say E
1
Consider a small length element dx, distance x away from origin.
Field due to this dE
1
=
x
2
kλdx
Integrating from x=d to x=d+l
GivesE
1
=
4πϵ
0
d(d+l)
λl
along -x direction
Now, E
2
is along the -y direction and same in magnitude.
Thus,
∣E∣=
2
∣E
1
∣=
4πϵ
0
d(d+l)
2
λl
Correct option is
C
4πϵ
0
d(d+l)
2
λl
Let's first find Electric field due to the rod on x-axis, say E
1
Consider a small length element dx, distance x away from origin.
Field due to this dE
1
=
x
2
kλdx
Integrating from x=d to x=d+l
GivesE
1
=
4πϵ
0
d(d+l)
λl
along -x direction
Now, E
2
is along the -y direction and same in magnitude.
Thus,
∣E∣=
2
∣E
1
∣=
4πϵ
0
d(d+l)
2
λl
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