Question

A thin uniform disc of mass M and radius R is rolling over a horizontal surface. Speed of it's top most point is found to be V w.r.t. surface over which it is rolling. Total kinetic energy of the disc will be given by?

Answer 1

Answer:

Explanation:

Dear Student,

Please find below the solution to the asked query:

We know that,

Angular Momentum = Moment of Inertia ×​ Angular momentum

Idisk = 12mR2

If the velocity of the disk about the axis of rotation is v,

then, its angular velocity = ω​ = Velocity Radius = vR

Now,

Angular momentum = 12mR2 × vR = 12×mvR