Question

A thin uniform disc of mass M and radius R is rolling over a horizontal surface. Speed of its top most point is found to be V w.r.t. surface over which it is rolling. Total kinetic energy of the disc will be given by-

Answer 1

Answer:

Angular Momentum = Moment of Inertia ×​ Angular momentum

Angular Momentum  = 12mR2

If the velocity of the disk about the axis of rotation is v,

then, its angular velocity = ω​ = Velocity Radius = vR

Now,

Angular momentum = 12mR2 × vR = 12×mvR

Explanation:

please do follow me

Answer 2

Answer:

This may be your answer I am not sure about it hope it might be helpful.

Explanation:

L=LCM+Mvr

⟹L=Iω+Mv R/2

⟹l= 1/2MR^2ω+Mv R/2

⟹L=MvR since ωR=v