Question

a thin uniform rod of length 2l is acted upon a constant torque . tje angular velocity changes from zero to omega in time t. the value of torque

Answer 1

Length of rod = 2l

I about centre of mass is -
$\frac{1}{12} m {(2l})^{2} \\ \frac{1}{3} m {l}^{2}$


$torque = I \: \alpha \\ = \frac{1}{3} m {l}^{2} \times \frac{w - 0}{t} \\ \frac{1}{3} \frac{m {l}^{2} w}{t}$
Hope it will help you!!

✨✨Option C

Answer 2

Heya.....

Here's your answer.....

The correct option is Option C.

Thanks...!!!

XD

Sorry baby 'wink'