A thin uniform rod of length L and mass m is swinging freely about a horizontal axis passing through its end . its maximum Angular speed is ω. its centre of mass rise ti a maximum height of [AIEEE 2009]
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- Explanation:- By conservation of energy ,
- initial total energy = final total energy
- TEᵢ = TEf
- 1/2Iω² = mgh
1/2× 1/3× ml²ω² = mgh
⟹1/2I²ω² = mgh
⟹ 1/2 × 1/3 mL²ω² = mgh
∴ moment of inertia of rod = mL²/3
⟹ h = L² ω² /6g Answer
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