Question

A thin uniform rod of mass 0.1 kg and length 0.3  m is smoothly hinged at its lower end .  It  is  then  released  from  rest  from  the  vertical  position.  What is its angular speed, in radian per  second, when it becomes horizontal?  (Moment of  inertia of the rod about one end is 3 X 10‐3 kg m2.)

A.  6.3    B.  10    C.  14    D.  50 

Answer 1

Answer:

The moment of inertia of rod about the axis passig through the end and perpendicular to its plane is I = 13ml2 For rotation of rod,Moment of ... x × F = Iα α = xF 13ml2 = 3xFml2 Here α is angular acceleration about hinge . ... the net force in vertical on centre of mass is = ma = 3xF2l This should be ... I=31​ml2.

1 answer

Explanation: