Question

A thin walled copper wire pipe 3.0m long and 2cm in diameter carries a net charge of 5.8 MC distributed uniformly. what is electric field 8cm from pipe axis
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Answer 1

Step-by-step explanation:

Given A thin walled copper wire pipe 3.0 m long and 2 cm in diameter carries a net charge of 5.8 MC distributed uniformly. what is electric field 8 cm

• We have from Gauss’s law we get
• EA = Q / εo where Q is enclosed charge and εo is permittivity of free space = 8.854 x 10^-12.
• Now A = 2πrL
• E = Q / 2πrLεo
• Here r = radius of Gausian cylinder or distance from pipe axis = 8 cm
• E = 5.8 x 10^-6 C / 2 x 3.14 x 8 x 10^-2 x 3 x 8.854 x 10^-12
• E = 5.8 x 10^-6 / 1334.47488 x 10^-6

Or E = 0.434 x 10^6 N / C

Reference link will be

https://brainly.in/question/14128502