Question

A thin wire 20 cm long is formed into a rectangle.If the width of this rectangle is 4 cm, what is its length.​

Answer 1

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A thin wire 20cm long is formed into a rectangle. If the width of the rectangle is 4cm, what is its length?

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The wire has formed the perimeter of rectangle. As such,

Petimeter of Rectangle = sum of all sides

As the length of wire was 20 cm, therefore the perimeter of rectangle is 20 cm.

Perimeter of rectangle =2 (length + width)

2 (Length + 4) = 20

Length + 4 = 20 / 2

Length + 4 = 10

Length = 10 - 4

Length = 6 cm.

Length of formed rectangle is 6 cm.

Answer => Length of formed rectangle from wire is 6 centimeter.

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Answer 2

Given:

A thin wire 20 cm long is formed into a rectangle. The width of this rectangle is 4 cm.

To find:

The length of the rectangle.

Solution:

The length of the rectangle is 6 cm.

To find the answer, we will follow these steps:

As we know that in a rectangle having length 'l' units and breadth 'b' units, the perimeter is given by using the formula.

$= 2(l + b)$

Now, as given, we have,

The length of the wire = 20 cm

As the same wire is formed into a rectangle,

So,

The perimeter of a rectangle = 20 cm

The width of the rectangle = 4 cm

Let the length of the rectangle be 'l' cm.

So,

$2( l + 4) = 20$

On solving the above, we get

$2l + 8 = 20$

$2l = 12$

$l = 6 \: cm$

Hence, the length of the rectangle is 6 cm.