Question

A thin wire 40 CM long is formed into a rectangle if the width of this rectangle is 8 CM what is length and area

Answer 1

Answer:-

Given:

Length of a wire = 40 cm.

A rectangle is made from this wire.

That means,

Perimeter of the rectangle formed = length of the wire.

Also,

Breadth of the rectangle formed = 8 cm.

We know that,

Perimeter of a rectangle = 2(length + breadth).

Let the length of the rectangle be x cm.

Hence,

→ 2(x + 8) = 40

→ 2x + 16 = 40

→ 2x = 40 - 16

→ 2x = 24

→ x = 24/2

→ x = 12

Hence,

• Length of the rectangle formed = x = 12 cm.

Now,

We know,

Area of a rectangle =length * breadth

→ Area of the rectangle = (12) * (8)

→ Area of the rectangle = 96 cm²

Therefore, the area of the rectangle formed is 96 cm².

Answer 2

★ QUESTION :

A thin wire 40cm long is formed into a rectangle. If the width of the rectangle is 8cm. What is the length and area ?

GIVEN :

• Length of the thin wire = 40cm
• Breadth of the rectangle = 8cm

TO FIND :

• The length and area of the rectangle = ?

STEP -BY-STEP EXPLAINATION :

⟼ Length of the thin wire = 40cm

⟼ Breadth of the rectangle = 8cm

So, as per the given information we are given year to find the length of the rectangle and area of the rectangle so first of all we will find length of the rectangle :

➠ For finding length of the rectangle :

⟹ Considering a length of the rectangle as 'x'

Therefore, perimeter of the rectangle :

• Perimeter = 2(l+b)

[ substituting values as per the given formula ]

⟹ 2(x + 8) = 40

⟹ 2x+16 = 40 [ replacing the sign ]

⟹ 2x = 40-16

⟹ 2x = 24

⟹ x = 24/2

⟹ x = 12cm [ Value of of the length of ]

━━━━━━━━━━━━━━━━━━━━━━━━━

Therefore, now you will have to find the area of the rectangle :

➠For finding area of the rectangle :

Fomula used for finding area of the rectangle :

• Area = length × Breadth

[ substituting the values as per formula ]

⟹ Area = length × Breadth

⟹ Area = 12 × 8

⟹ Area = 96cm²

Therefore, area of the rectangle = 96cm²