Question

A thin wire in the form of equilateral triangle of side 31.4 cm is bent into ring the diameter of the ring is

Answer 1

1 dm = 10 cm.

Side of equilateral triangle = 31.4 dm = 314 cm

Perimeter = 3 ( 314) = 942 cm.

Given, πd = 942 cm

πd = 942cm

d = 942 / 3.14

d = 300 cm...

d = 3m ..

Hope helped!