Question

a thin wire in the shape of a rectangle is straightened and bent again in the shape of a square if the sum of the length and breadth of the rectangle is 28 cm find the area of a square ​

Answer 1

Answer:

Given:

A wire is in shape of rectangle

where

length=20 cm.

breadth=12 cm.

Perimeter of rectangle =2(l+b)

=2(32)

[Perimeter =64 cm.]

now of wire is bent in shape of square

where side =a cm

now

Perimeter of rectangle = perimeter of square

64=4a

[a=16cm]

side of square formed is 16 cm.

Step-by-step explanation:

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