A thin wire is in the form of an equilateral triangle of side 11 cm. Find the area of a circle whose circumference is equal to the length of the wire
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Length of wire = perimeter of triangle = 3×4.4 = 13.2 cm
now
circumference of circle = length of wire
2πr = 13.2
r = 13.2×7/2×22
r = 2.1 cm
Area of circle = πr² = 22/7×(2.1)² = 13.86 cm²
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Length of wire = perimeter of triangle = 3×4.4 = 13.2 cm
now
circumference of circle = length of wire
2πr = 13.2
r = 13.2×7/2×22
r = 2.1 cm
Area of circle = πr² = 22/7×(2.1)² = 13.86 cm²
HOPE , IT HELPS.
FOLLOW ME . ✌
Kkaallii:
But I don't understand
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36
Answer:
Ans ) So for finding the circumference of the wire we need to find out the circumference of the triangle
Circumference of the triangle = Side + side +side or side x 3
= 11+11+11 or simply , 11 x 3 =33 cm
So , length of the wire = 33cm
Circumference of the circle = 33 cm
R=33/2π
=33/2 x 22/7
=21/4
Area of the circle =π x r square
22/7 x 21/4 x 21/4
=86 . 625 cm square
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