Question

A thin wire is in the shape of a circle of radius 77cm. It is bent into a square. Find the side of the square [taking π=22/7]

Answer 1

Answer:

Side of the square is 121 cm.

Step-by-step explanation:

Given: Radius (r) = 77cm

$\pi = \frac{22}{7}$

as it is given that it is bent into a square, therefore their Perimeters will be equal.

Thus, Circumference of Circle = Perimeter of square

$2\pi {r} = 4 \times s \: - (where \: s \: is \: the \: side \: of \: the \: square) \\ 2 \times \frac{22}{7} \times 77 = 4 \times s \\ 2 \times 22 \times 11 = 4 \times s \\ \frac{2 \times 22 \times 11}{4} = s \\ 11 \times 11 = s \\ s = 121 \: cm$

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Answer 2

The side of the square is 121 cm.

Given:

Radius of the circle of a thin wire, (r) = 77 cm

Pie, π = 22/7

A thin wire is in the shape of a circle is bent into a square.

To find: Side of the square

Formula used:

Circumference of the circle, C = 2πr

The perimeter of the square, P = 4 × side(s)

Solution:

Step1: Find the side of the square:

It is given that a thin wire is in the shape of a circle is bent into a square then their perimeter will be equal.

Circumference of circle = Perimeter of the square

2πr =  4 × side (s)

$2 \times \frac{22}{7} \times 77 = 4 \times side (s)$

[r = 77 cm]

44 × 11  = 4 × side

484 = 4 × side

Side, s =  $\frac{484}{4}$

Side, s = 121 cm

Side of the square (s) = 121 cm

Hence, the side of the square (s) is 121 cm.

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