Question

.A thin wire of length 20 cm is bent to form a rectangle. If the width of this rectangle is 4 cm, what is its LENGTH?

Answer 1

Perimeter = 2×(l+b)=20cm

Width of one side of RECTANGLE = 4cm

ATQ, 2×(l+4)= 20

$l + 4 = 20 \div 2 \\ l = 10 - 4 \\ l = 6cm \\ \\ \\ thank \: you$

GOOD NIGHT

Answer 2

Answer:

perimetre of rectangle

perimetre/2-leangth

20/2=10-4=6

Step-by-step explanation: